from.getPublicUrl()
获得公共bucket中资源的URL。
final res = supabase
.storage
.from('public-bucket')
.getPublicUrl('avatar1.png');
final publicURL = res.data;
Notes
- 所需的策略权限:
buckets
权限: noneobjects
权限: none
Examples
返回一个公共bucket中资源的URL
final res = supabase
.storage
.from('public-bucket')
.getPublicUrl('avatar1.png');
final publicURL = res.data;